Hello,

Tech Bulletin #388 explains that is possible to reduce the number of open
ports for client and server services.

The formula for service port range (in 7.1.3) is 2 + 3 + 2T + C.

In our environment, I know that T = 4 because I have 4 tape drives but the
"C" is "the maximum number of clients that can be backed up at any one
time".

How can I know this value? Is something related to client/server
parallelism? Or is the maximum number of clients in the group?

Thank you very much.

--

o o o  Manel Rodero                   | LCFIB - UPC
o o o  Helpdesk Manager               | Campus Nord - Modul B6
o o o  Laboratori de Calcul           | Jordi Girona, 1-3
U P C  Facultat Informatica Barcelona | 08034 Barcelona (Spain)
                                      |
       manel AT fib.upc DOT edu              | Tel: +00 34 93 401 6940
       http://www.fib.upc.edu/~manel  | Fax: +00 34 93 401 7040

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