Les Mikesell wrote at about 09:37:47 -0500 on Monday, September 16, 2013:
 > On Mon, Sep 16, 2013 at 8:52 AM, Dennis Ditte <dennis AT double-d DOT it> 
 > wrote:
 > > Hi,
 > >
 > > i need to execute two commands in the PreUserCmd/PostUserCmd. I tried it
 > > with this one:
 > > $Conf{DumpPreUserCmd} = 'touch /var/lock/backuppc/BackupPC && $sshPath
 > > -q -x -l root $host touch /var/lock/backuppc/BackupPC';
 > > and this one:
 > > $Conf{DumpPreUserCmd} = 'touch /var/lock/backuppc/BackupPC';
 > > $Conf{DumpPreUserCmd} = ' $sshPath -q -x -l root $host touch
 > > /var/lock/backuppc/BackupPC';
 > >
 > > At the first try, i can see in the logs that the Option -q is not valid
 > > FOR "touch". If i try the command as backuppc-user in the shell it works.
 > > The second try is also not working because only the last Line is executed.
 > >
 > > Is there a nice and easy way to do this?
 > 
 > Backuppc doesn't execute a shell to parse the commands before starting
 > them, so shell directives like && or ; aren't processed.  The easiest
 > way would be to put the commands you want to run in a shell script
 > file and execute the script from backuppc.
 > 

If the (implied) script is simple as per the OP's desire to run just
two shell commands, it would be easier to use 'bash -c'
I think the following would work...

$Conf{DumpPreUserCmd} = 'bash -c "touch /var/lock/backuppc/BackupPC;
                $sshPath -q -x -l root $host touch 
/var/lock/backuppc/BackupPC"';

I haven't tested that but I don't see why it wouldn't work...

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